;;; -*- Mode:LISP; Base:10 -*-

(defun foo ()
  (let ((a .5d0)
	(b 1.0d0) (c 2.0d0) (d 5.0d0)
	(e 50d0))
    #+foo(setq a (multiply-double a .25d0)
	  b (multiply-double b .25d0)
	  c (multiply-double c .25d0)
	  d (multiply-double d .25d0)
	  e (multiply-double e .25d0))
    (li:break (add-double b b)(add-double c c)(add-double d d)(add-double e e)
	      (subtract-double b b)(subtract-double c c)(subtract-double d d)(subtract-double e e)
	      (multiply-double b b)(multiply-double c c)(multiply-double d d)(multiply-double e e)
	      (divide-double b b)(divide-double c c)(divide-double d d)(divide-double e e)
))
  (loop))